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Ratios Solved Examples Q 1 On the off chance that ab=23 and bc=57, discover acRatio and Proportion quiz/questions and answers with explanation for various interview, competitive examination and entrance exam/test preparation Solved question papers with detailed answer description, explanation are given in this General Awareness Page 1 Section 84If a b c = 3 4 7, then the ratio (a b c) c is equal to a) 2 1 b) 14 3 c) 7 2 d) 1 2 Solution(By Examveda Team) $$\eqalign{ &\,\,\,\, {\text

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(a-b)^3+(b-c)^3+(c-a)^3 is equal to-The following table shows all the relational operators supported by C language Assume variable A holds 10 and variable B holds then − == Checks if the values of two operands are equal or not If yes, then the condition becomes true (A == B) is not true != Checks if the values of two operandsGiven that, AB=34=(3x2)(4x2)=68 BC= ABC=6 As consequent of the first ratio is equal to the antecedent of second ratio Part of solved Ratio and Proportions questions and answers >> Aptitude >> Ratio and Proportions

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Ratios Solved Examples Q 1 On the off chance that ab=23 and bc=57, discover acIf a,b,c are all nonzero and a b c = 0, prove that a2/bc b2/ca c2/ab = 3 asked Sep 14, 18 in Class IX Maths by aditya23 ( 2,139 points) polynomialsGrade K Module 3 Comparison of Length, Weight, Capacity, and Numbers to 10 After students observed, analyzed, and classified objects by shape into predetermined categories in Module 2, they now compare and analyze length, weight, volume, and, finally, number in Module 3

Output of the example above should be 10 c is set equal to a, because the condition a < b was true Remember that the arguments value_if_true and value_if_false must be of the same type, and they must be simple expressions rather than full statements(abc) 3 a 3 b 3 c 3 We can choose three "a"'s for the cube in one way C(3,3)=1, or we can choose an a from the first factor and one from the second and one from the third, being the only way to make a3 The coefficient of the cubes is therefore 1 (It's the same for a, b and c, of course) 3a 2 b3a 2 c Next, we consider the a 2 terms WeGeometrically the trivector a ∧ b ∧ c corresponds to the parallelepiped spanned by a, b, and c, with bivectors a ∧ b, b ∧ c and a ∧ c matching the parallelogram faces of the parallelepiped As a trilinear functional The triple product is identical to the volume form of the Euclidean 3space applied to the vectors via interior product

3 Mid point formula 1 2 1 2 x x y y, 2 2 4 Centriod formula 1 2 3 1 2 3 x x x y y y, 3 3 5 Area of triangle when their vertices are given,Int a = 10, b = , c;A 3 b 3 c 3 = (a b c)(a 2 b 2 c 2 ab ac bc) STOP (the assumption is the same;

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Define the sets A, B, C, and D as follows A = {3, 0, 1, 4, 17} B = {12, 5, 1, 4, 6} C = {x ∈ Z x is odd} D = {x ∈ Z x is positive} For each of the following set expressions, indicate whether the set is infinite or finiteI have the determinant \begin{vmatrix} 1 &1 &1 \\ a &b &c \\ a^3 &b^3 &c^3 \\ \end{vmatrix} How do I prove that this determinant is equal to $$ (ab)(bc)(ca)(abc) $$ Stack Exchange Network Stack Exchange network consists of 176 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learnExample Solve 8a 3 27b 3 125c 3 30abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 30abc) can be written as (2a) 3 (3b) 3 (5c) 3 (2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3 3abc

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Distributive Law The "Distributive Law" is the BEST one of all, but needs careful attention This is what it lets us do 3 lots of (24) is the same as 3 lots of 2 plus 3 lots of 4 So, the 3× can be "distributed" across the 24, into 3×2 and 3×4 And we write it like thisNow divide the two aspects via 3 so as that b may well be via itself on the left area Now the equation is b= (c5a)/(3) 8 x/y = w to remedy for x, lower back, you ought to hold all of the different words (y, w) to the different areaIf a,b,c are all nonzero and a b c = 0, prove that a2/bc b2/ca c2/ab = 3 asked Sep 14, 18 in Class IX Maths by aditya23 ( 2,139 points) polynomials

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What must be subtracted from 4x^42x^36x^22x6 so that the result is exactly divisible by 2x^2x1?There are various student are search formula of (ab)^3 and a^3b^3 Now I am going to explain everything below You can check and revert back if you like you can also check cube formula in algebra formula sheet a2 – b2 = (a – b)(a b) (ab)2 = a2 2ab b2 a2 b2 = (a –A0 the result is true (has a value of 1) only when both A0 are 1 (true) that is, when A is less than B and C is positive Two comparisons with a common variable linked by AND can be condensed with an implied AND

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To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If a(bc) =13 and c(a b) =57 then find (b ac)C = (a < b) ?Real coefficients) before collision is equal to P aftercollision, but there is a difference in

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To simplify the above expressions, start by expanding the binomials Note that we can expand the (ab)^3 , (bc)^3 , and (ca)^3 using the special product formulas for a cube of a binomialAsk questions, doubts, problems and we will help youTiger was unable to solve based on your input (ab)3 (bc)3 (ca)3 Step by step solution Step 1 11 Evaluate (ca)3 = c33ac23a2ca3 Step 2 Pulling out like terms 21 (ab)^3 (ab)^32b^3 (ab)3 −(a −b)3 −2b3 https//wwwtigeralgebracom/drill/ (a_b)~3 (ab)~32b~3/

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However, there is a problem when trying to prove (abc)^2 ≤ 3(abbcca), because, in fact, the opposite is true (abc)^2 ≥ 3(abbcca) You can see that if you expand (abc)^2, simplify, multiply by 2, and use the trivial inequalityIf A B = 2 3 and B C = 4 5, then A B C is 3 5 B5 4 6 C6 4 5 D8 12 15 Show Answer 8 12 15 Hence option D is 8 12A 3 b 3 c 3 = (a b c)(a 2 b 2 c 2 ab ac bc) STOP (the assumption is the same;

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How wide is a rectangular strip of land with length 3/4 mi and area 1/2 square mi?Output ab = 13 ab = 5 a*b = 36 a/b = 2 Remainder when a divided by b=1 The operators , and * computes addition, subtraction, and multiplication respectively as you might have expected In normal calculation, 9/4 = 225However, the output is 2 in the program It is because both the variables a and b are integers Hence, the output is also an integerReal coefficients) before collision is equal to P aftercollision, but there is a difference in

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How many 3/4cup servings are in 2/3 of a cup of yogurt?1 A and B together have Rs 1210 If 4/15 of A's amount is equal to 2/5 of B's amount How much amount B haveA 3 b 3 c 3 − 3abc = (a b c) (a 2 b 2 c 2 − ab − bc − ac) If (a b c) = 0, a 3 b 3 c 3 = 3abc Some not so Common Formulas

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If a,b, and c are all real positive numbers then it will be correct But anyway to prove this without knowing anything factor out the 3 in the portion on the right You will have 27(abc)>3(abc), then divide both sides by 3;Now divide the two aspects via 3 so as that b may well be via itself on the left area Now the equation is b= (c5a)/(3) 8 x/y = w to remedy for x, lower back, you ought to hold all of the different words (y, w) to the different areaFor the best answers, search on this site https//shorturlim/avymK A = b 3(4c) = substitute the letters to numbers A = 5 3(42) = 11 remember the PEMDAS 5 3(42) = solve the parenthesis first 5 3 (2) = multiply 3 to 2 5 6 = which is 6 then add 5 to 6 5 6 = 11

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Exercise In the plane, let A = (1, 2, 1), B = (3, 4, 1), C = (2, 1, 3) Use the dot product to compute all the side lengths and all the angles of this triangle Use the dot product to compute all the side lengths and all the angles of this triangleYour approach is intuitive and that was also the first thing I thought;PREVIEW ACTIVITY \(\PageIndex{1}\) Sets Associated with a Relation As was indicated in Section 72, an equivalence relation on a set \(A\) is a relation with a certain combination of properties (reflexive, symmetric, and transitive) that allow us to sort the elements of the set into certain classes

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There are various student are search formula of (ab)^3 and a^3b^3 Now I am going to explain everything below You can check and revert back if you like you can also check cube formula in algebra formula sheet a2 – b2 = (a – b)(a b) (ab)2 = a2 2ab b2 a2 b2 = (a –A = b means a is equal to b 2 a ≠ b means a does not equal b Operations 1 Addition If a = b then a c = b c 2 Subtraction If a = b then a – c = b– c 3 Multiplication If a = b then ac = bc 4 Division If a = b and c ≠ 0 then a/c = b/cExample Solve 8a 3 27b 3 125c 3 – 90abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 – 90abc) can be written as (2a) 3 (3b) 3 (5c) 3 – 3(2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3

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Click here👆to get an answer to your question ️ If A B = 1/2 1/3, B C = 1/2 1/3 , then A B C is equal toFor the best answers, search on this site https//shorturlim/avymK A = b 3(4c) = substitute the letters to numbers A = 5 3(42) = 11 remember the PEMDAS 5 3(42) = solve the parenthesis first 5 3 (2) = multiply 3 to 2 5 6 = which is 6 then add 5 to 6 5 6 = 111 A and B together have Rs 1210 If 4/15 of A's amount is equal to 2/5 of B's amount How much amount B have

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Factors ABCand (A 2B) (B 2C) (C A)2 2, either both are divisible by 3 or neither is divisible by 3 If A B Cis divisible by 3, then either A;B;Care all equal mod 3, in which case the second factor is clearly divisible by 3, or A;B;C are all di erent mod 3, in which case (A 2B) (B C) 2 (C A) is equal to 1 1 1 modulo 3 and theYou will have 9(abc)>(abc)If a b c =0, then a3b3 c3 is equal to (a) 0 (b) abc (c) 3abc (d) 2abc If the zeroes of a quadratic polynomial ax2 bx c are both positive, then a, b and c all have the same sign

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If the polynomial k 2 x 3 − kx 2 3kx k is exactly divisible by (x3) then the positive value of k is ____;Example Solve 8a 3 27b 3 125c 3 – 90abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 – 90abc) can be written as (2a) 3 (3b) 3 (5c) 3 – 3(2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3If a/3=b/4=c/7,then abc/c is equal to what?

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(In general, (a/b) ÷ (c/d) = ad/bc) How much chocolate will each person get if 3 people share 1/2 lb of chocolate equally?So basically what it is is that the problem is a^3b^3=c^3 but you changed it to cube root a^3 cube rootb^3 =cube rootc^3 which is equal to ab=c, so if what you say is right you would be able to use any terms for this second equation and it would fit the third so lets say 11=2 then plug in you get 11=8 doesn't workIf a b c = 3 4 7, then the ratio (a b c) c is equal to a) 2 1 b) 14 3 c) 7 2 d) 1 2 Solution(By Examveda Team) $$\eqalign{ &\,\,\,\, {\text

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